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since DA = DC, that makes DAC an isosceles triangle
∠ DCA → (180 - 138) ÷ 2 = 21°
∠ BCD → 21 + 22 = 43
∠ BCD + ∠ ADC = 138 + 43 = 181°
therefore ABCD is NOT a trapezium because the sum of ∠BCD and ∠ADC is NOT 180°.
In the figure, DA = DB = DC. ∠ADC = 138°, ∠BCE = 22° and ∠BAC = 47°.BED and AEC are straight lines.Circle the words that describe ABCD correctly in the following statement.ABCD (is / is not) a trapezium because the sum of ∠BCD and ∠ADC (is / is not) 180°. (1 mark)
Answer: ABCD is not a trapezium because the sum of ∠BCD and ∠ADC is not 180°.
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since DA = DC, that makes DAC an isosceles triangle
∠ DCA → (180 - 138) ÷ 2 = 21°
∠ BCD → 21 + 22 = 43
∠ BCD + ∠ ADC = 138 + 43 = 181°
therefore ABCD is NOT a trapezium because the sum of ∠BCD and ∠ADC is NOT 180°.